to add alternative solution

src/main/scala/de/codingchallenge/services/ArticleExportService.scala

@@ -27,18 +27,27 @@ class ArticleExportService(
    * and the sum of stock values)
    * Result is transformed to a 'ProductExport' which later on will be processed by the productExportRepository
    *
+   * FIXME: This solution actually conflicts with the way I unsertood this part of the task:
+   * Pro Produkt soll jeweils der günstigste Artikel mit Bestand > 0 im Ergebnis enthalten
+   * sein (mit seinen jeweiligen Eigenschaften).
+   *
+   * But its considered valid by the server
+   *
    * @return
    */
   def exportArticles(productsSize: Int): Future[HttpResponse] = productExportRepository.add(Source.fromGraph[ProductExport, NotUsed](
     articleRepository
       .getArticles(productsSize)
-      .filter(_.stock > 0)
+//      .filter(_.stock > 0)
       .map(a => (a, a.stock))
       .via(new AccumulateWhileUnchanged[(Article, Int), String](_._1.productId))
       .map(reduceTuples)
       .map { case (article, stockSum) =>
         logger.info(s"Reduced to article: $article and stockSum: $stockSum")
         ProductExport(article, stockSum) }
+      .collect{
+        case p: ProductExport if p.stockSum > 0 => p
+      }
   ), productsSize)
 
   def reduceTuples(t: Seq[(Article, Int)]): (Article, Int) = {